Calculate the density of the liquid if an aluminum ball with mass of m1 = 4.10kg has an apparent mass of m2 = 1.90kg when submerged in the liquid. the density of aluminum is 2.7

The density of the liquid = 1448.78 kg/m³

Explanation:

Density: This can be defined as the ratio of mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle

R.d = weight in air/upthrust = density of aluminium/density of liquid

W/U= D₁/D₂ Equation 1

making D₂ the subject of the equation

D₂ = D₁(U)/W Equation 2

Where W = Weight of aluminum in air, U = upthrust, D₁ = Density of aluminum, D₂ = Density of liquid

Given: W = mg = 4.1×9.8= 40.18 N, U = Lost in weight = 9.8(4.1-1.9)

U = 21.56 N, D₁ = 2.7 g/cm³ = 2700 kg/m³

Substituting into equation 2

D₂ = 2700(21.56)/40.18

D₂ = 1448.78 kg/m³

Thus the density of the liquid = 1448.78 kg/m³

t2 equal the displacement of the particle over the same time period if t2> t/2? hint: consider a sine wave starting at t1=0, then consider a closing wave starting at t1=0, for your explanatio

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq