Two skaters begin at rest. skater 1 has a smaller mass than skater 2. after they push off each
(3 points)
a. skater 1 experiences a greater change in momentum
lb. skater 2 experiences a greater change in momentum
c. skater 1 has a greater velocity than skater 2
d. skater 1 experiences a greater force

After they push off each other, Skater 1 has a greater velocity than Skater 2

By the application of collision of particles on the two skaters.

We know that skater 1 has a smaller mass and skater 2 has a larger mass than skater 1. It implies that the force of skater 2 will be greater than that of skater 1 since force (F) varies directly proportional to the mass of an object together with its acceleration.

So, when these two skaters collide, skater 2 exerts a greater force than skater 1 and the velocity of skater 1 will be increased and greater as a result of the collision with skater 2.

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As both the skater pushed each other with a force, skater 1 will acquire greater velocity than skater 2 with heavier mass.

Option C

Explanation:

Here we can understand the scenario with the example of a particle collision. When two particles of different masses, one being lighter and the other being heavier, there will be a movement and change in velocities.

Now, when these two particle collide with each other, there will be an equal and opposite thrust or reaction on both the particles. The particle with heavier mass will not be able to acquire more velocity because of its weight whereas the lighter particle will be pushed far away, being less in mass.

We can also say that the heavier particle will exert more force as compared to the lighter one and hence, can easily push it far away. this is all because the force is directly proportional to the mass of the object.

Hence, just like the particle, when two skater try to push each other with a significant amount of force, skater 2 will win to exert more force and therefore, skater 1 will acquire greater velocity as compared to skater 2.

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f=ma newton

f=100x2.5=250n