The horizontal beam in fig. e11.14 weighs 190 n, and its center of gravity is at its center. find (a) the tension in the cable and (b) the horizontal and vertical components of the force exerted on the beam at the wall.

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

The horizontal component is

The vertical component is

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

Put the value into the formula

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

Put the value into the formula

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

Put the value into the formula

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

the answer is 3.1 his answer is wrong mines is right

c) up is the direction the magnetic force is acting on the charge.