How is momentum conserved in a newton's cradle when one steel ball hits the other?

1. both balls have momentum to start, and they share it after the collision.
2. all the momentum starts in one ball, and after the collision, they share it.
3. momentum is not conserved in the steel balls of a newton's cradle.
4. all the momentum starts in one ball, and after the collision, it is all in the other ball.

Both balls have momentum to start,and they share it after collision

Explanation:both balls have momentum to start and they share it after collision

4. All the momentum starts in one ball, and after the collision, it is all in the other ball.

Explanation:

All the momentum starts in the first ball (the one is moving) . When this ball collides with the second ball, the first ball stops but its momentum it is transferred to the second ball, then to the third then fourth until it reaches the very last ball. Only the last ball has momentum now because is the only one moving.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.