An ideal gas is at 29 ∘c. the gas is cooled, reducing the thermal energy by 10.0%. what is the new temp?

The new temperature will be "26.1°C".

Given:

Initial temperature,

Reduced thermal energy,

The reduction will be:

=

=

hence,

The new temperature will be:

=

=

=

Thus the above answer is right

Learn more:

link

26.1°C

Explanation:

Initial temperature of an ideal gas is 29°C. If the thermal energy is reduced by 10% after cooling, the temperature of the gas has reduced by (10% of 29°C)

= 0.1×29

= 2.9°C

The new temperature = initial temperature - reduction

= 29°C - 2.9°C

= 26.1°C

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

your answer is c! hope this : )