Physics, 11.01.2020 20:31, CameronVand21

Aperson holding a 15.0 kg containing one 50.0 g bullet is riding on a train that is traveling at 75.0 km/h east. if the man fires the gun and the bullet moves with a velocity of 350 m/s east(relative to the train), what is the velocity of the gun relative to the ground

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answered: Jasten

The velocity of the gun relative to the ground is 19.73 m/

The given parameters;

mass of the person, m₁ = 15 kgmass of the bullet, m₂ = 50 g = 0.05 kgvelocity of the train, u₁ = 75 km/h = 20.83 m/svelocity of the bullet, u₂ = 350 m/s

Apply the principle of conservation of linear momentum, to determine the velocity of the gun relative to the ground;

$v(m_1 + m_2) = m_1 u_1 + m_2 u_2\\\\20.83(15 + 0.05) = 15u_1 + 0.05(350)\\\\313.49= 15u_1 + 17.5\\\\15u_1 = 295.99\\\\\mu_1 =\frac{295.99}{15} \\\\\mu_1 = 19.73 \ m/s$

Thus, the velocity of the gun relative to the ground is 19.73 m/s.

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answered: dm0321545

The velocity of the gun relative to the ground is 19.66 m/s

Explanation:

Given data,

The mass of the gun, M = 15.0 kg

The mass of the bullet, m = 50 g

The velocity of the train, v = 75 km/h

= 20.83 m/s

The velocity of bullet relative to train, V' = 350 m/s

The velocity of bullet relative to ground, V = 350 + 20

= 370 m/s

According to the law of conservation of momentum,

Mv' + mV' = 0

$v' = -\frac{mV'}{M}$

$v' = -\frac{0.050\times 350}{15}$

= -1.17 m/s

Therefore, the velocity of the gun with,

v₀ = V + v'

= 20.83 - 1.17

= 19.66 m/s

Hence, the velocity of the gun relative to the ground is 19.66 m/s

answered: Guest

1 the 4 is sig

answered: Guest

Initial velocity, u = 4.9 m/sfinal velocity = v m/sinitial height, h₁ = 245 m final height, h₂ = 0a = -9.8 m/s²time taken = t secondss = ut + 0.5at²⇒ (h₂-h₁) = ut + 0.5at²⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get t = 7.59sv = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is 69.48 m/s downward

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Aperson holding a 15.0 kg containing one 50.0 g bullet is riding on a train that is traveling at 75....