Abox of mass m1 = 20.0 kg is released from rest at a warehouse loading dock and slides down a 3.0 m-high frictionless chute to a waiting truck. it happens a box of m2 = 40.0 kg was left at the bottom of the chute. what is the impulse acting on m2 during the collision between the two boxes?

´To develop this problem we will use the concepts related to the conservation of momentum and the application of energy conservation equations to find the velocity of the mass after the collision, like this:

Velocity of the mass just before the collision

Therefore the momentum just before collision would be

Momentum after the collision

Since the momentum is conserved we have that

The velocity of mass after the collision is given by

Therefore the change in momentum of mass 2 is

Therefore the impulse acting on m2 during the collision between the two boxes is

c because the action was the roller coaster reaches bottom of hill (action) reaction would be blood tends to drain away from head

hope this !