Two charges separated by 1 m exert 1 n forces on each other. if the charges are pushed to 1/4m separation, the force on each charge will be

The force on each charge = 16 N

Explanation:

From coulombs law,

F = 1/4πε₀(q₁q₂)/d² Equation 1

q₁q₂ = F4πε₀d² Equation 2

Where F = force on the two charges, q₁ = charge on the first body, q₂ = charge on the second body, d = distance of separation, 1/4πε₀ = constant of proportionality.

When d = 1 m, F = 1 N,

Constant: 1/4πε₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 2,

q₁q₂ = 1×1²/9×10⁹

q₁q₂ = 1/9×10⁹  C²

When d = 1/4 m, q₁q₂ = 1/9×10⁹  C² and 1/4πε₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 1

F =  9×10⁹×1/9×10⁹ /(1/4)²

F = 1/(1/16)

F = 16 N

Therefore the force on each charge = 16 N

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

the answer for apex is the lowest