A30-kg shopping cart full of groceries sitting at the top of
a2.0-m hill begins to roll until it hits a stump at the bottom
ofthe hill. upon impact a, 0.25-kg can of peaches flies
horizontallyout of the shopping cart and hits a parked car with an
averageforce of 490n. how deep is the dent made in the car?

0.0102 m or 1 cm

Explanation:

Let g = 10m/s2

The potential energy of the shopping cart of the top of the hill is:

When the cart gets to the bottom of the hill, all this potential energy is converted to kinetic energy:

As the cart stop due to the stump, the can of peaches flies with the same speed.

By Newton's 3rd law, the car would exert a 490N force on the can too

The deceleration of the can would then be:

This force would stop the can, but not without making a dent, aka a traveled distance on the car skin

We can use the following equation of motion to find out the distance traveled by the can:

where v = 0 m/s is the final velocity of the can when it stops, = 40m/s is the initial velocity of the can when it hits, a = -1960 m/s2 is the deceleration of the can, and is the distance traveled, which we care looking for:

or 1 cm

they should be similar or the same

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