Aperson is standing on a level floor. his head, upper
torso, arms, and hands together weigh 438 n and have a center of
gravitythat is 1.28 m above the floor. his upper legs weigh 144 n
and havea center of gravity that is 0.760 m above the floor.
finally, hislower legs and feet together weigh 87 n and have a
center ofgravity that is 0.250 m above the floor. relative to the
floor, find the location of the center of gravity for the
entirebody.

Explanation:

Given data:

weigh (head+arms + head) w_1 = 438 N

centre of gravity y_1= 1.28 m

weigh (upper leg) w_2 = 144 N

Center of gravity y_2 = 0.760 m

weigh ( lower leg + feet) = 87 N

centre of gravity = y_3 = 0.250 m

location of center of gravity

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

not moving. pos accel,