In a diffraction experiment, light of 600nm wavelengthproduces
a first-order maximum 0.350 mm from the central maximum ona distant
screen. a second monochromatic source produces athird-order maximum
0.870 mm from the central maximum when itpasses through the same
diffraction grating. what is thewavelength of the light from the
second source?

λ≅

λ≅497 nm

Explanation:

In order to find the wavelength of the light from the second source we are going follow the following procedure.

Formula:

Nλ=d*x/l

Where:

N is the order of maximum

λ is the wavelength

d is the distance from central maximum

x/l is the ratio

For first monochromatic source:

We will find the ratio x/l.

=Nλ/d

For second monochromatic source:

Nλ=d*x/l

λ=

λ=

λ≅

λ≅497 nm

cancer risk hope this