An ideal gas initially at 4.00atm and 350 k is permitted
toexpand adibatically to 1.50 times its initial volume. findthe
final pressure and temperature if the gas is a)monoatomic;
b)diatomic with cv=.

Explanation:

It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is and final temperature is .

(a)   We know that for a monoatomic gas, value of is \frac{5}{3}[/tex].

And, in case of adiabatic process,

                = constant              

also,         PV = nRT

So, here     = 350 K,    ,  and  

Hence,      

          = 267 K

Also,   = 4.0 atm,   ,  and  

            = 2.04 atm

Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.

(b) For diatomic gas, value of is \frac{7}{5}[/tex].

As,         = constant              

also,         PV = nRT

= 350 K,    ,  and  

          = 289 K

And,   = 4.0 atm,   ,  and  

            = 2.27 atm

Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.

answer: the answer is a

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles