Ian infinite nonconducting sheet has surface charge density on one side. how far apart are equi-potential surfacews whose potentials sdiffer by 50 v?

8.85 × 10 ⁻³ m

Explanation:

The electric field produced by infinite sheet of charge relates by

E = σ / 2ε₀

where  σ = surface charge density = 0.1 μC/m² = 0.1 × 10⁻⁶C/m², ε₀ = 8.85 × 10⁻¹² C⁻²/Nm²

also

V = E Δs where Δs is the distance apart in meters, V is the voltage of the

make E subject of the formula

V/Δs = E

equate the two equation

V / Δs = σ / 2ε₀

make Δs subject of the formula

V2ε₀ / σ = Δs

substitute the values into the expression

Δs = (50 × 2 × 8.85 × 10⁻¹²)  / (0.1 × 10⁻⁶) = 8.85 × 10 ⁻³ m

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.