Asimple piping system consisting of a small pipe (diameter 6 cm) connected to a larger pipe (diameter 30 cm) is used to transfer and magnify force from one end to the other. the system is full of water and completely enclosed by two pistons, one on each end. if a force 11.2 n is exerted (additional to the forces already present) on the small piston, then how much additional force is exerted at the larger piston

280N

Explanation:

Pascal's law states that the pressure in a fluid is transmitted across every point in the fluid system.

Hence, the pressure in both tubes must remain same;

So, pressure = F1/A1 = F2/A2

where F1 = initial force on small pipe, A1 = area of small pipe

F2 = force on larger piston, A2 = area of larger piston

Given:

F1 = 11.2N

D1 = diameter of smaller pipe = 6 cm

D2 = diameter of larger piston = 15 cm

A1 = π*(r1)² = π*(6/2)² =π*9 (As radius, r = diameter/2)

A2 = π*(r2)² = π*(30/2)² =π*225

Hence 11.2/π*9 = F2/π*225

solving, we have

F2 = 280N

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.