A10.0-cm-long solenoid of diameter 0.400 cm is wound uniformly with 800 turns. a second coil with 50 turns is wound around the solenoid at its center. what is the mutual inductance of the combination of the two coils?

M = 6.32 x 10⁻⁶ H

Explanation:

given,

Length of solenoid = 10 cm = 0.1 m

diameter = 0.40 cm

radius = 0.2 cm = 0.002

number of turns, N₁ = 800

                            N₂ = 50

mutual inductance will be equal to  

           M = 6.32 x 10⁻⁶ H

hence, mutual inductance of the combination of two coil is equal to  M = 6.32 x 10⁻⁶ H

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