Two long thin parallel wires 13.0 cm apart carry 25-a currents in the same direction.
1. determine the magnitude of the magnetic field vector at a point 10.0 cm from one wire and 6.0 cm from the other.
2. determine the direction of the magnetic field vector at that point.

3.33 x 10⁻⁵ T

Explanation:

given,

current carried by two parallel wire = 25 A

distance between two wire = 13 cm

1) Let p be the distance between two wire

         p = 13 cm = 0.13 m

         a = 10 cm = 0.1 m

         b = 6 cm = 0.06 m

 using cosine law

       θ = 105.96°

       θ = 106°(approximately)

now, magnetic field on one wire

      B₁ = 5 x 10⁻⁵ T

now, magnetic field on another wire

      B₂ = 8.33 x 10⁻⁵ T

resultant field,

=

=

= 3.33 x 10⁻⁵ T

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.