Suppose that you have a reflection diffraction grating with n= 125 lines per millimeter. light from a sodium lamp passes through the grating and is diffracted onto a distant screen. part a
two visible lines in the sodium spectrum have wavelengths 498\rm nm and 569 \rm nm. what is the angular separation \delta \theta of the first maxima of these spectral linesgenerated by this diffraction grating?
part b
how wide does this grating need to be to allow you to resolvethe two lines 589.00 and 589.59 nanometers, which are a well knownpair of lines for sodium, in the second order (m=2)?

3.99322032 mm

Explanation:

n = Lines per mm = 125

Seperation between slits is given by

= 498 nm

= 569 nm

We have the expression

For first maximum m = 1

Angular separation is given by

Angular separation is

Now

= 589 nm

= 589.59 nm

We have the relation

Width is given by

The width is 3.99322032 mm

answer: option c.

explanation:

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia