One method of determining the location of the center of gravity of a person is to weigh the person as he/she lies on a board of negligible weight supported by two scales. in one example the height of the man is 190 cm; when he lies on the board, the left scale reads 450 n and the right scale reads 390 n. the center of gravity of the man relative to his feet on the right is?

x = 1.018 m

Explanation:

given,

height of man = 190 cm

                       = 1.9 m

scale reading on left = 450 N

scale reading on the right = 390 N

Let center of gravity of man be x distance from feet, feet is on right side.

For system to be in equilibrium moment about center should be equal to zero.

∑M = 0

now,

450(1.9 - x ) - 390 × x = 0

450(1.9 - x ) = 390 × x

855 - 450 x = 390 x

840 x = 855

 x = 1.018 m

hence, point of center of gravity from feet is equal to x = 1.018 m

we need some answer choices, or something like that

explanation:

the device is called “ rocket engine”