Arifle is aimed directly at the bulls eye of a target 75 meters away. if the bullet has a speed of 250 m/s, how far below the bulls eye will the bullet hit

Explanation:

Given

Distance of target d=75 m

velocity of bullet v=250 m/s

First taking horizontal motion

as there is no acceleration is horizontal direction therefore

where u=initial velocity

=acceleration

t=time

In this time Vertical distance moved by Bullet is

here

the body's situation won't change the forces are equal opposit and on the same body

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂