A45.2-kg wagon is towed up a hill inclined at 18.5∘ with respect to the horizontal. the tow rope is parallel to the incline and has a tension of 191 n in it. assume that the wagon starts from rest at the bottom of the hill, and neglect friction. how fast is the wagon going after moving 83.8 m up the hill?

The speed is 29.9 m/s

Explanation:

The force created from gravity due to the wagon mass is:

140.55 N pull the wagon down. Two parallel rope with tension of 191N creates 382 N on the wagon. Therefore:

241.45 N force is pulling up the wagon. Then we need to find the acceleration of the wagon under this force:

acceleration is 5.34 m/s^2. The distance is multiplication of acceleration and square of the time.

After 5.6 second the wagon will ride 83.8 m up to hill. And the speed of wagon at that point is:

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards