A60.7 kg astronaut is floating in space. she takes her 3.1 kg astronaut drill from her toolbelt and throws it to the right. it now has a momentum of p to the right and she has a momentum of to the left.

p to the left

Explanation:

According to law of conservation of momentum "total momentum of an isolated system remains constant".

we consider astronaut and astronaut drill as an isolated system. If the drill gain momentum p to the right so in order for momentum to remain constant the astronaut will gain the same momentum but in opposite direction i.e momentum p to the left.

Initial momentum = 0 ( before she throw astronaut belt)

Final momentum = p - p = 0 (After she throw astronaut belt)

Hence momentum of the system remains constant i.e zero.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

a skateboard rolling across the street - apex