Metal 1 has a larger work function than metal 2. both are illuminated with the same short-wavelength ultraviolet light. part a do photoelectrons from metal 1 have a higher speed, a lower speed, or the same speed as photoelectrons from metal 2?

Explanation:

Einstein's equation for photoelectric effect is as follows

hυ = Φ + 1/2 mv²

hc/λ = Φ + 1/2 mv²

λ is wavelength of light used ,  Φ is work function and v is velocity of electrons ejected .

In the equation above , if λ is constant , LHS and therefore RHS will be constant .

In RHS , if work function  Φ is greater , velocity v must be lower to make RHS constant .

Therefore metal 1 having higher work function must see lower velocity of electrons or this plate must eject electrons with lower velocity.

a and c

c is 100% but i am confused in a

i think the answer is a and b

i wish you luck