Amajorette in the rose bowl parade tosses a baton into the air with an initial angular velocity of 2.5 rev/s. if the baton undergoes a constant acceleration while airborne of 0.2 rev/s2 and its angular velocity is 0.8 rev/s when the majorette catches it, how many revolutions does it make in the air?
Answers: 2
= initial angular velocity = 2.5 revsā»Ā¹
= final angular velocity = 0.8 revsā»Ā¹
= Angular acceleration = - 0.2 revsā»Ā²
= Angular displacement 
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Amajorette in the rose bowl parade tosses a baton into the air with an initial angular velocity of 2...
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