A2.7-cm-tall object is 20 cm to the left of a lens with a focal length of 10 cm . a second lens with a focal length of 48 cm is 52 cm to the right of the first lens.

a. calculate the distance between the image and the second lens. b.calculate the image height.

Answer

given,

height of object = 2.7 cm

distance left of lens (u₁)= 20 cm

focal length of lens(f₁)= 10 cm  

the distance of image

   v₁ = 20 cm

magnification of first lens

    m₁ = -1

distance of object from the second lens

   u₂ = 52-20 = 32 cm

   f₂ = 48 cm

now,

   v₁ = 624 cm

magnification of first lens

    m₁ = -12

total magnification

m = m₁ m₂

m = (-1)(-12)

m = 12

height of image

h' = -32.4 cm

a) distance between image and second lens is equal to 624 cm

b) height of image is equal to 32.4 cm

the force on the thing and the distance the force moves the thing

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2