Ahoop of mass 50 kg rolls without slipping. if the center-of-mass of the hoop has a translational speed of 4.0 m/s, the total kinetic energy of the hoop is

a. 0. 20 kj
b. 0.40 kj
c. 1.1 kj
d. 3.9 kj
e. none of these is correct.

total kinetic energy = 800 J

so correct option is e. None of these is correct

Explanation:

given data

hoop  mass = 50 kg

speed = 4.0 m/s

to find out

total kinetic energy of hoop

solution

we know that translational kinetic energy that is  

translational kinetic energy = 0.5×m×v²    ....................1

translational kinetic energy = 0.5×50×4²

translational kinetic energy = 400 J

and rotational kinetic energy  will be

rotational kinetic energy = 0.5 × moment of inertia × (angular speed )²    ............2

here

moment of inertia = mass × R²

and angular speed  =

so rotational kinetic energy = 0.5×m×v²

rotational kinetic energy = 0.5×50×4²

rotational kinetic energy = 400 J

so total kinetic energy = 400 J + 400 J

total kinetic energy = 800 J

so correct option is e. None of these is correct

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.