Collapse the star had a mass of 2 times the mass of the sun and a radius the same as the sun. before the collapse it rotates once every 10 days. after the collapse it has not lost any mass but now has a radius of only 10 km. what is its rotation rate in rev/s after the collapse

0.2 milisecond

Explanation:

Let the mass of sun is M

mass of star = 2 M

initial radius of the star, R = radius of sun = 7 x 10^5 km

initial time period, T = 10 days

final radius, R' = 10 km

mass remains same.

As no external torque is acting on the star so its angular momentum remains constant.

So, Angular momentum before collapsing = Angular momentum after collapsing

I x ω = constant

T' = 2.04 x 10^-9 days

T' = 0.2 milisecond

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray