A4.6 kg hockey puck is moving at 7.4 m/s, and is given a 14.4 kg m/s impulse in the same direction that it is moving. what is the final velocity of the hockey puck?

The final velocity of the hockey puck = 10.53 m/s

Explanation:

Impulse: Impulse of a body is defined as the product of Force of a body and the time. Or it can also be defined as the product of the mass of a body and its change in velocity. The S.I units of impulse are, Ns or kgm/s.

Mathematically, impulse can be represented as,

I = m(v-u)

making v the subject of formula in the equation above,

v = (I/m)+u Equation 1

Where I = impulse of a body, m = mass of the body, u = initial velocity of the body, v = final velocity of the body.

Given: I = 14.4 kgm/s, m = 4.6 kg, u = 7.4 m/s.

Substituting these values into equation 1

v = (14.4/4.6)+7.4

v = 3.13 + 7.4

v = 10.53 m/s

Therefore the final velocity of the hockey puck = 10.53 m/s

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y