A200 kg wood crate sits in the back of a truck. the coefficients of friction between the crate and the truck are = 0.9 and = 0.5. the truck starts off up a 20° slope. what is the maximum acceleration the truck can have without the crate slipping out the back?

Maximum acceleration of the truck is 5.25 m/s^2

Explanation:

To find the maximum acceleration the truck first we need to calculate friction between truck and wood. Because of wood is not moving, coefficient of c_{s} need to be used for it. Then the formula will be:

1657.62 Newton is the friction.

So force against friction need to be at most 1657.62 N. Then equation will be:

Maximum acceleration of the truck need to be 5.25 m/s^2

f is prop to m1xm2 double m1 double force

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y