Atoy rocket is launched straight up by using a spring. the rocket is initially pressed down on the spring so that the spring is compressed by 9 cm. if the spring constant is 1050 n/m and the mass of the rocket is 50 g, how high will the rocket go? you may neglect the effects of air resistance.

Rocket will go to a height of 8.678 m

Explanation:

Mass of the rocket m = 50 gram = 0.05 kg

Spring constant k = 1050 N /m

Spring is stretched to 9 cm

So x = 0.09 m

Work done in stretching the spring

From energy conservation this energy will convert into potential energy

Potential energy is equal to , here m is mass, g is acceleration due to gravity and h is height

So

So rocket will go to a height of 8.678 m

8.68 m

Explanation:

compression in spring, x = 9 cm = 0.09 m

Spring constant, K = 1050 N/m

mass of rocket, m = 50 g = 0.05 kg

Let it go upto height h.

Use conservation of energy

Potential energy stored in spring = potential energy of the rocket

0.5 x 1050 x 0.09 x 0.09 = 0.05 x 9.8 x h

h = 8.68 m

Thus, the rocket will go upto height 8.68 m.

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.