When being unloaded from a moving truck, a 16.0- kilogram suitcase is placed on a flat ramp inclined at 40.0 o. when released from rest, the suitcase accelerates down the ramp at 1.36 m/s². what is the coefficient of kinetic friction between the suitcase and the ramp?

0.65812

Explanation:

m = Mass of suitcase = 16 kg

= Incline angle = 40°

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration of the block = 1.36 m/s²

f = Frictional force

The normal force is given by

In x direction

Frictional force is given by

The coefficient of kinetic friction between the suitcase and the ramp is 0.65812

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft