Ajet plane flying 600 m/s experiences an acceleration of 4g when pulling out of the dive. what is the radius of curvature of the loop in which the plane is flying?

R = 9200 m

Explanation:

given,

speed of the plane = 600 m/s

acceleration = 4 g

Radius of curvature of loop = ?

we know,

angular acceleration

.........(1)

we know,

v = r ω

putting value of r in equation (1)

   ω = 0.0653 rad/s

600 = 0.0653 x r

R = 9183 m

R = 9200 m (approx)

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