Amotorcyclist is traveling along a road and accelerates for 4.84 s to pass another cyclist. the angular acceleration of each wheel is 6.76 rad/s2, and, just after passing, the angular velocity of each is 77.6 rad/s, where the plus signs indicate counterclockwise directions. what is the angular displacement of each wheel during this time?

296 rad

Explanation:

time (t) = 4.84 s

angular acceleration (a) = 6.76 rad/s^{2}

angular velocity (ω) = 77.6 rad/s

what is the angular displacement (θ) of the wheel during this time?

from the equation of angular kinematics angular displacement (θ) = ω₀t +

where

        ω = ω₀ + at

        77.6 = ω₀ + (6.76 x 4.84)

        ω₀ = 77.6 - (6.76 x 4.84) = 44.88 rad/s

angular displacement (θ) =ω₀t +  

angular displacement (θ) =

angular displacement (θ) = 296 rad

i cant see the choices man

no. dot product   =0 when vecs at right angles