Four uniform spheres, with masses ma = 200 kg, mb = 250 kg, mc = 1700 kg, and md = 100 kg, have (x, y) coordinates of (0, 50 cm), (0, 0), (-80 cm, 0), and (40 cm, 0), respectively. what is the net gravitational force f2 on sphere b due to the other spheres?

in the anticlockwise direction from the positive x- axis.

Explanation:

Given are the masses of various spheres with their names in subscript:

Now their respective coordinate positions (in cm) are as given below:

Now force on B due to A:

Now force on B due to C:

Now force on B due to D:

We observe that the forces due to masses  C&D act opposite in direction.

So, the net force in the x-direction:

in the positive x-direction

We have only one force in y-direction due to mass A.

So,

in the positive y-direction.

Now the net force:

Now the direction of this force with respect to x-axis:

in the anticlockwise direction from the positive x- axis.

3.64 x 10^-5 N

Explanation:

mA = 200 kg

mB = 250 kg

mc = 1700 kg

mD = 100 kg

Force on B due to A

FA = 1.334 x 10^-5 N

Force on B due to C

FC = 4.43 x 10^-5 N

Force on B due to D

FD = 1.042 x 10^-5 N

FD and Fc are opposite to each other, so net of Fc and FD is F'.

F' = (4.43 - 1.042) x 10^-5 N towards left

F' = 3.39 x 10^-5 N

Now F' and FA are perpendicular to each other, So net force on B due to all other

F = 3.64 x 10^-5 N

Thus, the net force on B due to other is 3.64 x 10^-5 N.

the answer is false. this is because for ice to melt, it requires latent heat of melting. latent heat means heat energy required to change phase without any increase in temperatures. therefore, the ice will take energy from the environment to melt hence atmospheric temperatures will reduce.