Aball is thrown vertically upward from the ground. its distance in feet from the ground in t seconds is s equals negative 16 t squared plus 240 t. after how many seconds will the ball be 864 feet from the ground?

t₁ = 3 s

Explanation:

In this exercise, the vertical displacement equation is not given

        y = 240 t + 16 t²

Where y is the displacement, 240 is the initial velocity and 16 is half the value of the acceleration

Let's replace

      864 = 240 t + 16 t²

Let's solve the second degree equation

    16 t² + 240 t - 864 = 0

Let's divide by 16

    t² + 15 t - 54 = 0

The solution of this equation is

     t = [-15 ± √(15 2 - 4 1 (-54)) ] / 2 1

     t = [-15 ±√(225 +216)] / 2

     t = [-15 + - 21] / 2

We have two solutions.

     t₁ = [-15 +21] / 2

     t₁ = 3 s

     t₂ = -18 s

Since time cannot have negative values, the correct t₁ = 3s

explanation:

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