The volume of a sphere is increasing at a rate of 25\pi25π25, pi cubic meters per hour. at a certain instant, the volume is \dfrac{32\pi}{3} 3 32π start fraction, 32, pi, divided by, 3, end fraction cubic meters.

It indicates no change in temperature and the process of matter changing its state

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j