An astronaut has left the international space station to test a new space scooter. her partner measures the following velocity changes, each taking place in a time interval 11.3 s . what are the average acceleration in each interval?

1.) at the beginning of the interval the astronaut is moving toward the right along the x-axis at 15.0 m/s, and at the end of the interval she is moving toward the right at 5.30 m/s.
a =
2.) at the beginning she is moving toward the left at 5.30 m/s. and at the end she is moving toward the left at 15.0 m/s.
a = ? ?
3.) at the beginning she is moving toward the right at 15.0 m/s, and at the end she is moving toward the left at 15.0 m/s.
a =

Answer

given,

time interval = 11.3 s

a) initial velocity, vi = 15 m/s

   final velocity, v_f = -5.30 m/s

             a = -1.79 m/s²

   the direction is along left side

b)  initial velocity, vi = -5.30 m/s

   final velocity, v_f = -15 m/s

             a = -0.858 m/s²

   the direction is along left side

c) initial velocity, vi = 15 m/s

   final velocity, v_f = -15 m/s

             a = -2.65 m/s²

   the direction is along left side

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.