If r = 12 cm, m = 520 g, and m = 20 g (below), find the speed of the block after it has descended 50 cm starting from rest. solve the problem using energy conservation principles. (treat the pulley as a uniform disk.)

v = 0.84 m/s

Explanation:

given,

R = 12 cm

M (mass of pulley )= 520 g

m  (mass of block)=  20 g

s = 50 cm = 0.5 m

using conservation of energy

Potential energy = Kinetic energy

     and v = r ω

      v = √0.7

      v = 0.84 m/s

it is easily magnetized.