Ahorizontal aluminum rod 4.8 cm in diameter projects 5.6 cm from a wall. a 1200 kg object is suspended from the end of the rod. the shear modulus of aluminum is 3.0 ? 1010 n/m2. neglect the rod's mass.(a) find the shear stress on the rod. (n/m2)(b) find the vertical deflection of the end of the rod. (m)

(a) Shear stress will be 4780487.80

(b)

Explanation:

We have given length of the aluminium rod l = 4.8 cm = 0.048 m

Diameter

Area

Shear modulus

Mass m = 1200 kg

So weight

(a) So hear stress P

(b) Now shear modulus is

So

Now strain is given by

So

its c i just checked it

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach