Listena bullet traveling at 5.0 × 102 meters per second is brought to rest by an impulse of 50. newton-seconds. what is the mass of the bullet? 2.5 × 104 kg1.0 × 101 kg1.0 × 10-1 kg1.0 × 10-2 kg

The mass of the bullet = 1.0 × 10⁻² kg

Explanation:

Impulse: The impulse of a body is defined as the product of force and time, or it can also be defined as the product of mass and change in velocity of that body. The S.I unit of impulse is newton - second or kg m/s

impulse = I = M(u-v)

Making M the subject of the equation above,

M = I/(u-v) Equation 1

Where I = impulse of the bullet, M = mass of the bullet, V = final velocity of the bullet, u = initial velocity of the bullet.

Given: I = 5.0 Newton - second, v = 0 (brought to rest), u = 5.0 ×10² m/s

Substituting these values into equation 1

M = 5/ (5.0 ×10²)

M = 1.0 × 10⁻² kg.

The mass of the bullet = 1.0 × 10⁻² kg

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask

i think they are all correct

explanation:

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