The temperature of the iron cube, 5 cm on edge, should be changed by what amount for the volume of the cube to increase by 0.35 cm3. (the coefficient of linear expansion of iron is 1.2 x 10-5 per 0c )

change in temperature of iron cube is 233 degree

Explanation:

given data

length = 5 cm

volume increase dV = 0.35 cm³

coefficient linear expansion α = 1.2 ×

to find out

change in temperature of iron cube

solution

we get here first initial volume that is

initial volume = 5³

initial volume = 125 cm ³

and we consider here change in temperature is dT

so volume increase will be here as

dV = V × α × dT    ......................1

0.35 = 125 ×  1.2 × × dT    

solve we get

dT = 233 degree

so change in temperature of iron cube is 233 degree

force tends to be low and long diustance masses are high