Three blocks are connected by massless cords and rest on a frictionless horizontal surface. the blocks are pulled to the right. mass m1 = 2 m2 = 3 m3, with m1 on the left and m3 on the right. if the pulling force is equal to 90 n, then the tension in the cord between m1 and m2

Explanation:

First draw a free body diagram

Let T is the tension in cord between m1 and m2

T=m1×a

Where a for system will be same

F=ma. a=F/m1+m2+m3

m1=2m2

m3=2/3m2

a=270/11m2

T=m1×270/11m2=24.5m1/m2

the answer would be c. motion and direction

i hope this : )

0.11 m/s and 0.28 m/s should be correct