Arubbit gets down from a rump which its /\x=0.85m in 0.5s, the rubbit's mass is 2kg, what is the net force?

13.6 N

Explanation:

The equation of motion for the rabbit is:

(1)

Where:

is the distance traveled by the rabbit

is the rabbit's initial velocity, assuming it started from rest

is the time

is the acceleration

Isolating :

(2)

(3)

(4)

On the other hand, the force is given by:

(5)

Where is the mass of the rabbit

Substituting (4) in (5):

(6)

Finally:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

falling water hydro = water .. spectcular places these plants are