Calculate a. the heat that must be supplied to a 500.0 g copper kettle containing 400.0 g of water to raise its temperature from 22.0°c to the boiling point of water, 100.0°c. b. what percentage of the heat is used to raise the temperature of the water?

Explanation:

dH copper = mCdT copper

(Specific Heat of copper=0.385 J/g C )  

dH = 500 g (0.385 J/g C) (78 C rise)

dH = 15,015 Joules

dH water =  m C dT water

(Specific Heat of copper=4.184 J/g-C)  

dH = 400 g (4.184 J/g-C) (78 C rise)

dH = 130,540 Joules

total heat = 15,015 + 130,540 = 145,555 Joules

(130,540 Joules  / 145,555 Joules) x 100 = 89.7 %

If we consider that we have 3 Significant Figures,

then, the answers become ,

15.0 KJ must be added for Copper

130.5 KJ must be added for Water

and the total of 145 KJ must be added in the kettle with the water

89.7 %  of heat goes to the Water

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

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