A10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. at time t=0, the resulting mass-spring system is disturbed from its rest state by the force f(t)=140cos(8t). the force f(t) is expressed in newtons and is positive in the downward direction, and time is measured in seconds.

K= 1000 N-m

Explanation:

It is assumed that we asked to find the spring constant k of the spring

We know that under equilibrium condition

weight of the object = force applied by the spring

given m =10 Kg

x= extension in the spring = 9.8 cm

mg=kx

K= 1000 N-m

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