Imagine a spring made of a material that is not very elastic, so that the spring force does not satisfy hooke’s law, but instead satisfies the equation f = −α x + β x3 , where α = 5.2 n/m and β = 700 n/m3 . calculate the work done by the spring when it is stretched from its equilibrium position to 0.12 m past its equilibrium. answer in units of mj.

     W = -1.152 mJ

Explanation:

given,

F = −α x + β x³

α = 5.2 N/m and β = 700 N/m³

Work done = ?

length of stretch = ?

we know,

W = F . ds

now,

     W = -0.001152 J

    W = -1.152 mJ

work done by the spring is equal to W = -1.152 mJ

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