You and your friend are running at each other from 200m apart. after 10 seconds and having passed the 50m mark on your side, you see your friend has already gone 60m on his. what will your average velocity need to be for the remaining time in order for you to both have covered the same amount of distance, assuming he maintains a constant speed?

average speed = 7.50 m/s

Explanation:

given data

distance = 200 m

time = 10 seconds

passed = 50m

already gone = 60 m

to find out

average velocity need to be for the remaining time

solution

we get here first Velocity of friend v that is express as

velocity =

velocity =

velocity = 6 m/s

and time taken to reach half the way is here as

time taken =

time taken = 16.67 seconds

and now distance to be covered is

distance to be covered =  100 m - 50 m

distance to be covered = 50 meters

and remaining distance cover in time = 16.67 sec - 10 sec

remaining distance cover in time = 6.67 seconds

so average speed will be here as

average speed =  

average speed = 7.50 m/s

b

explanation:

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.