To practice problem-solving strategy 33.2 linear polarization. unpolarized light of intensity 30 w/cm2 is incident on a linear polarizer set at the polarizing angle θ1 = 14 ∘. the emerging light then passes through a second polarizer that is set at the polarizing angle θ2 = 162 ∘. note that both polarizing angles are measured from the vertical. what is the intensity of the light that emerges from the second polarizer?

To solve this problem it is necessary to apply the concepts related to the law of Malus.

The light intensity after passing through the first polarizer is given as

Where,

I = Intensity of unpolarized light

The expression for malus law is given as

Where

\theta = Angle between the first and second polarizers

 = Intensities of the light after passing through the first and second polarizers respectively.

The intensity of light after passing first polarizer ( Perpendicular to the surface) is

The angle between the first and second polarizers is given by

The expression for Malus law is given by

Therefore the intensity of the light after passing through both the polarizer is

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )