I've tried following the equations and doing this on my own, but after 5 tries i still come up empty handed (wrong) everytime!by showing me how to do these problems! 4. the continuity equation provides a second relation between the va and vb, and the cross-sectional area at points a and b: latex: v_\text{a}a_\text{a}=v_\text{b}a_\t ext{b}vaaa=vbabin terms of the diameters d and d: latex: v_\text{a}d^2=v_\text{b}d^2vad2=vbd 2 [equation 2]question 4if the diameters are d = 1.3 cm, and d = 12 cm,, what is the ratio of the speeds, vb/va? 5.if we combine equations 1 and 2, we obtain: latex: v_\text{a}^2=\frac{2gh}{\frac{d^4}{ d^4}-1 }va2=2ghd4d4−1 [equation 2a]on the other hand, the water surface (i. e., point a) is moving with constant acceleration. therefore, its speed v at any given distance y from the initial level is: latex: v^2-v_\text{a}^2=2ayv2−va2=2aywhen the surface reaches the bottom of the bottle (where y = h), the final speed is v = 0. then, the last expression becomes: latex: v_\text{a}^2=-2ayva2=−2ay [equation 2b]comparing equations 2a and 2b, we can obtain an expression for the acceleration of the surface: a = [equation 3]