The electric field of a sinusoidal electromagnetic wave obeys the equation e=? (375v/m)sin[(5.97×1015rad/s)t+(1.99 ×107rad/m)x] .part b: what is the amplitude of the magnetic field of this wave? part cwhat is the frequency of the wave? b = ? t

Explanation:

The equation of electric field is

E = 375 Sin(5.97 x 10^15 t + 1.99 x 10^7 x)

Compare with the standard equation

E = Eo Sin(ωt + kx)

(b) Amplitude of electric field, Eo = 375 V/m

Amplitude of magnetic field, Bo = Eo / c = 375 / (3 x 10^8)

Bo = 125 x 10^-8 Tesla

Bo = 1.25 x 10^-6 Tesla

(c) ω = 5.97 x 10^15 rad

2 x 3.14 x f = 5.97 x 10^15

f = 0.95 x 10^15 Hz

f = 9.5 x 10^14 Hz

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j