36 of 50 constants a 89.0-kg refrigerator sits on the floor. the coefficient of static friction between the refrigerator and the floor is 0.60. what is the minimum force that one needs to exert on the refrigerator to start the refrigerator sliding?

523.32 N

Explanation:

Frictional Force: This is a type of contact 523.force that opposes motion between two surface in contact. It is measured in newton. Mathematically, frictional force can be expressed as,

F = μR equation 1

Where F = frictional force, μ = coefficient of static friction, R = Normal reaction.

On a level surface, Normal reaction = Weight

Since the floor is a level surface,

R = W equation 2

Where W = weight of the refrigerator.

W = mg equation 3

m = mass of the refrigerator, g = acceleration due to gravity

Where m = 89 kg, g = 9.8 m/s²

Substituting these values into equation 3,

R = W = 89 × 9.8 = 872.2 N

∴ R = 872.2 N, μ= 0.6

also substituting this values into equation 1

F = 872.2 × 0.6

F = 523.32 N

The minimum force needed to make the refrigerator to slid = The force required to overcome friction = Frictional force

∴The minimum force needed to make the refrigerator to slid = 523.32 N

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